What is the derivative of f(x)=7x^3-5x+8 ?

The derivative of f(x)=7x^3-5x+8 is 21x^2-5

What is the first derivative of f(x)=7x^3-5x+8 ?

The first derivative of f(x)=7x^3-5x+8 is 21x^2-5

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derivative of

f (x) = 7 x^{3} - 5 x + 8

21 x^{2} - 5

Solution steps

\frac{d}{d x} (7 x^{3} - 5 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 x^{3}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (8)

\frac{d}{d x} (7 x^{3}) = 21 x^{2}

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (8) = 0

= 21 x^{2} - 5 + 0

Simplify

= 21 x^{2} - 5

cos (3 t)

\frac{d}{d x} (\frac{10 x}{( x ^{2} + 1 ) ^{2}})

\frac{d y}{d t} = (t + y)^{2} - 1

x \to 5 lim (9 - x^{2})

\int \frac{y}{y + 3} d y

What is the derivative of f(x)=7x^3-5x+8 ?
The derivative of f(x)=7x^3-5x+8 is 21x^2-5
What is the first derivative of f(x)=7x^3-5x+8 ?
The first derivative of f(x)=7x^3-5x+8 is 21x^2-5