What is the sum from n=1 to infinity of ((e^n))/n ?

The sum from n=1 to infinity of ((e^n))/n is diverges

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sum from n=1 to infinity of ((e^n))/n

n = 1 \sum \infty \frac{( e ^{n} )}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{e ^{n}}{n}

Apply Series Ratio Test:

diverges

= diverges

y^{^{'''}} + 13 y^{^{''}} - 9 y^{^{'}} - 405 y = 0

y^{^{'}} = 3 - \frac{2 y}{200 + x}

\int \frac{2 + x}{9 + x ^{2}} d x

\int \frac{2}{( 25 + x ^{2} ) ^{\frac{3}{2}}} d x

\int \frac{1}{6} sin (6 x) d x

What is the sum from n=1 to infinity of ((e^n))/n ?
The sum from n=1 to infinity of ((e^n))/n is diverges