What is area x=4y-8,x=sqrt(4y+1) ?

The answer to area x=4y-8,x=sqrt(4y+1) is (37sqrt(37))/(24)

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area x=4y-8,x=sqrt(4y+1)

area

x = 4 y - 8, x = 4 y + 1

\frac{37 37}{24}

Decimal Notation

9.37759 \dots

Solution steps

Isolate

y

for

x = 4 y - 8 : y = \frac{x + 8}{4}

Isolate

y

for

x = 4 y + 1 : y = \frac{x ^{2} - 1}{4} {x \geq 0}

Apply the area formula:

\int_{\frac{1 - 37}{2}}^{\frac{1 + 37}{2}} \frac{x + 8}{4} - \frac{x ^{2} - 1}{4} d x

Solve

\int_{\frac{1 - 37}{2}}^{\frac{1 + 37}{2}} \frac{x + 8}{4} - \frac{x ^{2} - 1}{4} d x : \frac{37 37}{24}

The area is:

= \frac{37 37}{24}

\int \frac{1}{x \cdot ln ^{2} ( x )} d x

\int 3 cot (x) d x

\int sin (\frac{1}{4} x) d x

\frac{\partial}{\partial x} ((x - u)^{2})

x \to 3 lim ((x - 3)^{2})

What is area x=4y-8,x=sqrt(4y+1) ?
The answer to area x=4y-8,x=sqrt(4y+1) is (37sqrt(37))/(24)