What is the derivative of f(x)=x^2+x-7 ?

The derivative of f(x)=x^2+x-7 is 2x+1

What is the first derivative of f(x)=x^2+x-7 ?

The first derivative of f(x)=x^2+x-7 is 2x+1

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derivative of

f (x) = x^{2} + x - 7

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (7) = 0

= 2 x + 1 - 0

Simplify

= 2 x + 1

x \to 2 lim (x^{2} - 3 x + 4)

\frac{d}{d x} (\frac{x ^{6}}{5 - x ^{5}})

x = 9 y^{2}, x = 20 + 4 y^{2}

x \to \infty lim (e)

What is the derivative of f(x)=x^2+x-7 ?
The derivative of f(x)=x^2+x-7 is 2x+1
What is the first derivative of f(x)=x^2+x-7 ?
The first derivative of f(x)=x^2+x-7 is 2x+1