What is area x=9y^2,x=20+4y^2 ?

The answer to area x=9y^2,x=20+4y^2 is No Solution

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area x=9y^2,x=20+4y^2

area

x = 9 y^{2}, x = 20 + 4 y^{2}

No Solution

Solution steps

Isolate

y

for

x = 9 y^{2} : y = \frac{x}{3}, y = - \frac{x}{3}

Isolate

y

for

x = 20 + 4 y^{2} : y = \frac{x - 20}{2}, y = - \frac{x - 20}{2}

f_{1} (x) = \frac{x}{3}

f_{2} (x) = - \frac{x}{3}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{x}{3} = - \frac{x}{3} : x = 0

\frac{x}{3} = \frac{x - 20}{2} : x = 36

\frac{x}{3} = - \frac{x - 20}{2} :

No Solution for

x \in R

- \frac{x}{3} = \frac{x - 20}{2} :

No Solution for

x \in R

- \frac{x}{3} = - \frac{x - 20}{2} : x = 36

\frac{x - 20}{2} = - \frac{x - 20}{2} : x = 20

Curves not bounded

= No Solution

\frac{d}{d x} (x + 5 x + \frac{1}{7})

x \to \infty lim (e)

\int_{0}^{1} (x + 6) (x - 7) d x

\int (2520 x) 3 5 + 3 x d x

\frac{d ^{2}}{d x ^{2}} (\frac{1 - 4 x}{1 + 4 x})

What is area x=9y^2,x=20+4y^2 ?
The answer to area x=9y^2,x=20+4y^2 is No Solution