What is the derivative of 2sqrt(1+x) ?

The derivative of 2sqrt(1+x) is 1/(sqrt(1+x))

What is the first derivative of 2sqrt(1+x) ?

The first derivative of 2sqrt(1+x) is 1/(sqrt(1+x))

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\frac{d}{d x} (2 1 + x)

\frac{1}{1 + x}

Solution steps

\frac{d}{d x} (2 1 + x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (1 + x)

Apply the chain rule:

\frac{1}{2 1 + x} \frac{d}{d x} (1 + x)

= \frac{1}{2 1 + x} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= 2 \cdot \frac{1}{2 1 + x} \cdot 1

Simplify

2 \cdot \frac{1}{2 1 + x} \cdot 1 : \frac{1}{1 + x}

= \frac{1}{1 + x}

f (x) = (x + 1)^{2}

y^{^{''}} + 324 y = sec (18 x)

x \to 18 lim (\frac{x ^{2}}{2} - \frac{9}{x})

y^{^{'}} = 2 (3 x + y)^{2} - 1

\int_{1}^{2} \frac{x + 2 x ^{2}}{x} d x

What is the derivative of 2sqrt(1+x) ?
The derivative of 2sqrt(1+x) is 1/(sqrt(1+x))
What is the first derivative of 2sqrt(1+x) ?
The first derivative of 2sqrt(1+x) is 1/(sqrt(1+x))