What is the integral from 1 to 100 of 1/(x^2) ?

The integral from 1 to 100 of 1/(x^2) is 99/100

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integral from 1 to 100 of 1/(x^2)

\int_{1}^{100} \frac{1}{x ^{2}} d x

\frac{99}{100}

Decimal Notation

0.99

Solution steps

\int_{1}^{100} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{100}

= [- \frac{1}{x}]_{1}^{100}

Compute the boundaries:

\frac{99}{100}

= \frac{99}{100}

\frac{d y}{d x}, 2 x = y^{4}

x \to 0 lim (\frac{x}{- 4 x ^{3} - 8 x})

\frac{\partial}{\partial t} (\frac{( s - 3 r )}{t})

\int 2 x (x^{2} + 1)^{4} d x

\int 1 + x^{2} x^{5} d x

What is the integral from 1 to 100 of 1/(x^2) ?
The integral from 1 to 100 of 1/(x^2) is 99/100