What is (\partial}{\partial t}(\frac{(s-3r))/t) ?

The answer to (\partial}{\partial t}(\frac{(s-3r))/t) is -(s-3r)/(t^2)

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(\partial}{\partial t}(\frac{(s-3r))/t)

\frac{\partial}{\partial t} (\frac{( s - 3 r )}{t})

- \frac{s - 3 r}{t ^{2}}

Solution steps

\frac{\partial}{\partial t} (\frac{( s - 3 r )}{t})

Treat

s, r

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (s - 3 r) \frac{\partial}{\partial t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= (s - 3 r) \frac{\partial}{\partial t} (t^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= (s - 3 r) (- 1 \cdot t^{- 1 - 1})

Simplify

(s - 3 r) (- 1 \cdot t^{- 1 - 1}) : - \frac{s - 3 r}{t ^{2}}

= - \frac{s - 3 r}{t ^{2}}

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What is (\partial}{\partial t}(\frac{(s-3r))/t) ?
The answer to (\partial}{\partial t}(\frac{(s-3r))/t) is -(s-3r)/(t^2)