What is the derivative of f(x)=\sqrt[4]{x}sin(x) ?

The derivative of f(x)=\sqrt[4]{x}sin(x) is (sin(x))/(4x^{3/4)}+\sqrt[4]{x}cos(x)

What is the first derivative of f(x)=\sqrt[4]{x}sin(x) ?

The first derivative of f(x)=\sqrt[4]{x}sin(x) is (sin(x))/(4x^{3/4)}+\sqrt[4]{x}cos(x)

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derivative of

Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d}{d x} (sin (x)) = cos (x)

\frac{1}{4 x ^{\frac{3}{4}}} sin (x) = \frac{sin ( x )}{4 x ^{\frac{3}{4}}}

\int ln ∣ x ∣ sin (x) d x

9 x^{3} (x^{2} - 2)

f (x) = \frac{( x + 1 ) ^{2}}{3 x - 4}

\int \frac{3 - 18 x}{4 - 9 x ^{2}} d x

\int \frac{1}{( 1 - 6 x ) ^{4}} d x

What is the derivative of f(x)=\sqrt[4]{x}sin(x) ?
The derivative of f(x)=\sqrt[4]{x}sin(x) is (sin(x))/(4x^{3/4)}+\sqrt[4]{x}cos(x)
What is the first derivative of f(x)=\sqrt[4]{x}sin(x) ?
The first derivative of f(x)=\sqrt[4]{x}sin(x) is (sin(x))/(4x^{3/4)}+\sqrt[4]{x}cos(x)