What is the derivative of y=x^2+2x-4 ?

The derivative of y=x^2+2x-4 is 2x+2

What is the first derivative of y=x^2+2x-4 ?

The first derivative of y=x^2+2x-4 is 2x+2

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derivative of

y = x^{2} + 2 x - 4

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4) = 0

= 2 x + 2 - 0

Simplify

= 2 x + 2

y = x^{3} + 3 x^{2}

\frac{\partial}{\partial x} (2 cos (y))

\frac{1}{5 x ^{2}}

\frac{\partial}{\partial x} (tan (3 x))

y^{^{''}} - 9 y^{^{'}} + 20 y = 0

What is the derivative of y=x^2+2x-4 ?
The derivative of y=x^2+2x-4 is 2x+2
What is the first derivative of y=x^2+2x-4 ?
The first derivative of y=x^2+2x-4 is 2x+2