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Popular >

y^'=x+4y-2

Solution

y^{^{'}} = x + 4 y - 2

Solution

y = - \frac{x}{4} + \frac{7}{16} + c_{1} e^{4 x}

Solution steps

y^{'} (x) = x + 4 y - 2

Solve linear ODE:

y = - \frac{x}{4} + \frac{7}{16} + c_{1} e^{4 x}

y = - \frac{x}{4} + \frac{7}{16} + c_{1} e^{4 x}

Popular Examples

integral of (x-3)^{-2}

\int (x - 3)^{- 2} d x

limit as x approaches 0 of (2^x-3^x)/x

x \to 0 lim (\frac{2 ^{x} - 3 ^{x}}{x})

tangent of y=(x^3-16x)^{12},(-4,0)tangent of

y = (x^{3} - 16 x)^{12}, (- 4, 0)

derivative of (5x^2)/(sqrt(x))derivative of

\frac{5 x ^{2}}{x}

y^{^{'}} + y = e^{- x}

Frequently Asked Questions (FAQ)

What is the solution for y^'=x+4y-2 ?
The solution for y^'=x+4y-2 is y=-x/4+7/16+c_{1}e^{4x}