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Popular >

y^'+y=e^{-x}

Solution

y^{^{'}} + y = e^{- x}

Solution

y = \frac{x}{e ^{x}} + \frac{c _{1}}{e ^{x}}

Solution steps

y^{'} (x) + y = e^{- x}

Solve linear ODE:

y = \frac{x}{e ^{x}} + \frac{c _{1}}{e ^{x}}

y = \frac{x}{e ^{x}} + \frac{c _{1}}{e ^{x}}

Graph

Popular Examples

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\int \frac{e ^{- y}}{y} d y

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\int_{0}^{2} (x - 1)^{2} d x

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3 5 + 6 x^{6}

(\partial)/(\partial x)(5-x^2+xy-2^2)

\frac{\partial}{\partial x} (5 - x^{2} + x y - 2^{2})

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=e^{-x} ?
The solution for y^'+y=e^{-x} is y= x/(e^x)+(c_{1})/(e^x)