What is the derivative of (2x+1)^4 ?

The derivative of (2x+1)^4 is 8(2x+1)^3

What is the first derivative of (2x+1)^4 ?

The first derivative of (2x+1)^4 is 8(2x+1)^3

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derivative of

(2 x + 1)^{4}

8 (2 x + 1)^{3}

Solution steps

\frac{d}{d x} ((2 x + 1)^{4})

Apply the chain rule:

4 (2 x + 1)^{3} \frac{d}{d x} (2 x + 1)

= 4 (2 x + 1)^{3} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= 4 (2 x + 1)^{3} \cdot 2

Simplify

= 8 (2 x + 1)^{3}

x \to \infty lim (lo g_{2} (\frac{( x + 2 )}{( 2 \cdot x + 1 )}))

\int_{1}^{8} x - 1 d x

x^{2} x^{3} + 1

\int \frac{sec ^{2} ( θ )}{tan ( θ )} d θ

x^{^{''}} - 2 x^{^{'}} - 3 x = 0

What is the derivative of (2x+1)^4 ?
The derivative of (2x+1)^4 is 8(2x+1)^3
What is the first derivative of (2x+1)^4 ?
The first derivative of (2x+1)^4 is 8(2x+1)^3