What is the derivative of ln(4x^2) ?

The derivative of ln(4x^2) is 2/x

What is the first derivative of ln(4x^2) ?

The first derivative of ln(4x^2) is 2/x

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\frac{d}{d x} (ln (4 x^{2}))

\frac{2}{x}

Solution steps

\frac{d}{d x} (ln (4 x^{2}))

Apply the chain rule:

\frac{1}{4 x ^{2}} \frac{d}{d x} (4 x^{2})

= \frac{1}{4 x ^{2}} \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (4 x^{2}) = 8 x

= \frac{1}{4 x ^{2}} \cdot 8 x

Simplify

\frac{1}{4 x ^{2}} \cdot 8 x : \frac{2}{x}

= \frac{2}{x}

sin^{2} (x), sin^{4} (x), 0, π

\frac{d}{d x} ((2)^{x})

4 x - x^{2}

\int cos (9 x) sin (5 x) d x

y^{3} - (18 x + 6) + 3 x y^{2} \frac{d y}{d x} = 0

What is the derivative of ln(4x^2) ?
The derivative of ln(4x^2) is 2/x
What is the first derivative of ln(4x^2) ?
The first derivative of ln(4x^2) is 2/x