What is the integral of 4ln(x^2-1) ?

The integral of 4ln(x^2-1) is 4(xln(x^2-1)+ln|x+1|-ln|x-1|-2x)+C

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integral of 4ln(x^2-1)

\int 4 ln (x^{2} - 1) d x

4 (x ln (x^{2} - 1) + ln ∣ x + 1 ∣ - ln ∣ x - 1 ∣ - 2 x) + C

Solution steps

\int 4 ln (x^{2} - 1) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int ln (x^{2} - 1) d x

Apply Integration By Parts

: x ln (x^{2} - 1) - \int \frac{2 x ^{2}}{x ^{2} - 1} d x

= 4 (x ln (x^{2} - 1) - \int \frac{2 x ^{2}}{x ^{2} - 1} d x)

\int \frac{2 x ^{2}}{x ^{2} - 1} d x = - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ + 2 x

= 4 (x ln (x^{2} - 1) - (- ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ + 2 x))

Simplify

= 4 (x ln (x^{2} - 1) + ln ∣ x + 1 ∣ - ln ∣ x - 1 ∣ - 2 x)

Add a constant to the solution

= 4 (x ln (x^{2} - 1) + ln ∣ x + 1 ∣ - ln ∣ x - 1 ∣ - 2 x) + C

\int 2 x^{2} - 4 x - 6 d x

\frac{d}{d x} (x^{\frac{9}{x}})

\frac{d y}{d t} = 2100 - 300 (\frac{y}{17000})

\int \frac{5}{x ^{6}} d x

\frac{d}{d x} (ln ((x + 3)^{- 1}))

What is the integral of 4ln(x^2-1) ?
The integral of 4ln(x^2-1) is 4(xln(x^2-1)+ln|x+1|-ln|x-1|-2x)+C