What is the solution for y^{''}+2y=-12x ?

The solution for y^{''}+2y=-12x is y=c_{1}cos(sqrt(2)x)+c_{2}sin(sqrt(2)x)-6x

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y^{''}+2y=-12x

y^{^{''}} + 2 y = - 12 x

y = c_{1} cos (2 x) + c_{2} sin (2 x) - 6 x

Solution steps

y^{''} (x) + 2 y = - 12 x

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) - 6 x

y = c_{1} cos (2 x) + c_{2} sin (2 x) - 6 x

h \to 0 lim (\frac{( 2 + h ) ^{3} - 8}{h})

x \to \infty lim (x)

f (x) =, 4 x^{3} + 2 t + 9

f (x) = (2 x + 3)^{1.4}

What is the solution for y^{''}+2y=-12x ?
The solution for y^{''}+2y=-12x is y=c_{1}cos(sqrt(2)x)+c_{2}sin(sqrt(2)x)-6x