What is (\partial)/(\partial x)(2y+z^3-xz) ?

The answer to (\partial)/(\partial x)(2y+z^3-xz) is -z

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(\partial)/(\partial x)(2y+z^3-xz)

\frac{\partial}{\partial x} (2 y + z^{3} - x z)

- z

Solution steps

\frac{\partial}{\partial x} (2 y + z^{3} - x z)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) + \frac{\partial}{\partial x} (z^{3}) - \frac{\partial}{\partial x} (x z)

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (z^{3}) = 0

\frac{\partial}{\partial x} (x z) = z

= 0 + 0 - z

Simplify

= - z

y = \frac{2 x}{x + 1}

7 (sin (t) y^{^{'}} + cos (t) y) = cos (t) sin^{3} (t)

\frac{d y}{d x} = \frac{- 2 x}{y}, y (0) = 1

\frac{d}{d x} (6 x + e^{- x})

(x^{2} y - x) d y + y d x = 0

What is (\partial)/(\partial x)(2y+z^3-xz) ?
The answer to (\partial)/(\partial x)(2y+z^3-xz) is -z