What is ((1+sin(t))/(1-cos(t)))^2 ?

The solution to ((1+sin(t))/(1-cos(t)))^2 is ((1+sin(t))^2)/((1-cos(t))^2)

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simplify ((1+sin(t))/(1-cos(t)))^2

simplify

(\frac{1 + sin ( t )}{1 - cos ( t )})^{2}

\frac{( 1 + sin ( t ) ) ^{2}}{( 1 - cos ( t ) ) ^{2}}

Solution steps

(\frac{1 + sin ( t )}{1 - cos ( t )})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 1 + sin ( t ) ) ^{2}}{( 1 - cos ( t ) ) ^{2}}

\int_{0}^{\infty} 9 sin^{2} (x) d x

(x - y^{2} x) d x + (y - x^{2} y) d y = 0

x = 6 - y^{2}, x = y

y = x^{3} - 3 x + 2

x^{3} - 3 x + 2

What is ((1+sin(t))/(1-cos(t)))^2 ?
The solution to ((1+sin(t))/(1-cos(t)))^2 is ((1+sin(t))^2)/((1-cos(t))^2)