What is the derivative of (g(x))/(1+f(x)) ?

The derivative of (g(x))/(1+f(x)) is x/(1+xf)

What is the first derivative of (g(x))/(1+f(x)) ?

The first derivative of (g(x))/(1+f(x)) is x/(1+xf)

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derivative of

\frac{g ( x )}{1 + f ( x )}

\frac{x}{1 + x f}

Solution steps

\frac{d}{d g} (\frac{gx}{1 + f x})

Treat

x, f

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{x}{1 + f x} \frac{d g}{d g}

Apply the common derivative:

\frac{d g}{d g} = 1

= \frac{x}{1 + f x} \cdot 1

Simplify

= \frac{x}{1 + x f}

x \to - 3 lim (\frac{3 x}{9 - x ^{2}})

\int u^{7} d u

\frac{d y}{d x} = \frac{( x - 1 )}{y + 2}

\int \frac{x + 2}{4 - 2 x - x ^{2}} d x

\int_{0}^{1} 13 \frac{1}{x ^{p}} d x

What is the derivative of (g(x))/(1+f(x)) ?
The derivative of (g(x))/(1+f(x)) is x/(1+xf)
What is the first derivative of (g(x))/(1+f(x)) ?
The first derivative of (g(x))/(1+f(x)) is x/(1+xf)