What is the derivative of 6x^2cos(x)cot(x) ?

The derivative of 6x^2cos(x)cot(x) is 6(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)

What is the first derivative of 6x^2cos(x)cot(x) ?

The first derivative of 6x^2cos(x)cot(x) is 6(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)

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derivative of

6 x^{2} cos (x) cot (x)

6 (2 x cos (x) cot (x) + (- cos (x) - cot (x) csc (x)) x^{2})

Solution steps

\frac{d}{d x} (6 x^{2} cos (x) cot (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (x^{2} cos (x) cot (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = cos (x) cot (x)

= 6 (\frac{d}{d x} (x^{2}) cos (x) cot (x) + \frac{d}{d x} (cos (x) cot (x)) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (cos (x) cot (x)) = - cos (x) - cot (x) csc (x)

= 6 (2 x cos (x) cot (x) + (- cos (x) - cot (x) csc (x)) x^{2})

\int_{1}^{3} x^{3} + 2 x - 3 d x

f (x) = (3 x + 5)^{2}

\int \frac{1}{cos ( x ) + 1} d x

f (x) = 3 x^{2} + 2 x + 1

x^{2} - 4 x + 7, 2 x^{2} - 3 x + 1

What is the derivative of 6x^2cos(x)cot(x) ?
The derivative of 6x^2cos(x)cot(x) is 6(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)
What is the first derivative of 6x^2cos(x)cot(x) ?
The first derivative of 6x^2cos(x)cot(x) is 6(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)