What is the solution for (dy}{dx}+\frac{2y)/x = 1/(x^2) ?

The solution for (dy}{dx}+\frac{2y)/x = 1/(x^2) is y= 1/x+(c_{1})/(x^2)

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(dy}{dx}+\frac{2y)/x = 1/(x^2)

\frac{d y}{d x} + \frac{2 y}{x} = \frac{1}{x ^{2}}

y = \frac{1}{x} + \frac{c _{1}}{x ^{2}}

Solution steps

\frac{d y}{d x} + \frac{2 y}{x} = \frac{1}{x ^{2}}

Solve linear ODE:

y = \frac{1}{x} + \frac{c _{1}}{x ^{2}}

y = \frac{1}{x} + \frac{c _{1}}{x ^{2}}

x^{2} - 4, y = 0, x = - 4, x = 3

\frac{d}{d x} (ln (\frac{a + b x}{a - b x}))

\frac{1}{s ^{2} + 4 s + 12}

\frac{d}{d x} ((7 x + 3)^{2})

\frac{d}{d x} ((3 x^{3} + 1) (- 4 x^{2} - 3)^{4})

What is the solution for (dy}{dx}+\frac{2y)/x = 1/(x^2) ?
The solution for (dy}{dx}+\frac{2y)/x = 1/(x^2) is y= 1/x+(c_{1})/(x^2)