What is the derivative of f(x)=3x^2+2x-3 ?

The derivative of f(x)=3x^2+2x-3 is 6x+2

What is the first derivative of f(x)=3x^2+2x-3 ?

The first derivative of f(x)=3x^2+2x-3 is 6x+2

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derivative of

f (x) = 3 x^{2} + 2 x - 3

6 x + 2

Solution steps

\frac{d}{d x} (3 x^{2} + 2 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (3)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= 6 x + 2 - 0

Simplify

= 6 x + 2

\int x \cdot sin (k x) d x

y^{^{''}} - 8 y^{^{'}} = 0

\frac{1}{ln ( 3 x )}

\int 3 x e^{2 x} d x

y^{^{'}} = \frac{1}{2 y}

What is the derivative of f(x)=3x^2+2x-3 ?
The derivative of f(x)=3x^2+2x-3 is 6x+2
What is the first derivative of f(x)=3x^2+2x-3 ?
The first derivative of f(x)=3x^2+2x-3 is 6x+2