What is (\partial)/(\partial y)(zy^2(t+1)) ?

The answer to (\partial)/(\partial y)(zy^2(t+1)) is 2zy(t+1)

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(\partial)/(\partial y)(zy^2(t+1))

\frac{\partial}{\partial y} (z y^{2} (t + 1))

2 zy (t + 1)

Solution steps

\frac{\partial}{\partial y} (z y^{2} (t + 1))

Treat

z, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z (t + 1) \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= z (t + 1) \cdot 2 y^{2 - 1}

Simplify

= 2 zy (t + 1)

\int e^{- s i n (x)} cos (x) d x

x \to 0 - lim (1 - \frac{3}{x} + \frac{1}{x ^{2}})

y = (1 + 4 x)^{\frac{3}{2}}

\int x sin (\frac{nπ x}{3}) d x

\frac{1}{s ^{2} ( s ^{2} + 1 ^{2} )}

What is (\partial)/(\partial y)(zy^2(t+1)) ?
The answer to (\partial)/(\partial y)(zy^2(t+1)) is 2zy(t+1)