What is the limit as t approaches-2 of (t^4-8)/(2t^2-3t+8) ?

The limit as t approaches-2 of (t^4-8)/(2t^2-3t+8) is 4/11

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limit as t approaches-2 of (t^4-8)/(2t^2-3t+8)

t \to - 2 lim (\frac{t ^{4} - 8}{2 t ^{2} - 3 t + 8})

\frac{4}{11}

Decimal

0.36363 \dots

Solution steps

t \to - 2 lim (\frac{t ^{4} - 8}{2 t ^{2} - 3 t + 8})

Plug in the value

t = - 2

= \frac{( - 2 ) ^{4} - 8}{2 ( - 2 ) ^{2} - 3 ( - 2 ) + 8}

Simplify

\frac{( - 2 ) ^{4} - 8}{2 ( - 2 ) ^{2} - 3 ( - 2 ) + 8} : \frac{4}{11}

= \frac{4}{11}

\frac{d y}{d t} - 2 t y = t

\frac{d y}{d x} = - 10 x y

\int t sin (t) cos (t) d t

x \to \infty lim (x y)

\frac{d y}{d x} + \frac{y}{x} = 4 x^{8} y^{2}

What is the limit as t approaches-2 of (t^4-8)/(2t^2-3t+8) ?
The limit as t approaches-2 of (t^4-8)/(2t^2-3t+8) is 4/11