What is the solution for y^{''}-20y^'+181y=0 ?

The solution for y^{''}-20y^'+181y=0 is y=e^{10t}(c_{1}cos(9t)+c_{2}sin(9t))

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y^{''}-20y^'+181y=0

y^{^{''}} - 20 y^{^{'}} + 181 y = 0

y = e^{10 t} (c_{1} cos (9 t) + c_{2} sin (9 t))

Solution steps

y^{''} (t) - 20 y^{'} (t) + 181 y = 0

Solve linear ODE:

y = e^{10 t} (c_{1} cos (9 t) + c_{2} sin (9 t))

y = e^{10 t} (c_{1} cos (9 t) + c_{2} sin (9 t))

\int (x^{2} - 5)^{2} d x

\int \frac{x}{x} d x

y = 11 x^{- 2} + 7 x^{3} - 5 x

x \to 2 lim (4)

x \to - 6 + lim (tan (\frac{π x}{4}))

What is the solution for y^{''}-20y^'+181y=0 ?
The solution for y^{''}-20y^'+181y=0 is y=e^{10t}(c_{1}cos(9t)+c_{2}sin(9t))