What is (\partial)/(\partial y)(e^{xy^2+z^2}) ?

The answer to (\partial)/(\partial y)(e^{xy^2+z^2}) is e^{xy^2+z^2}*2xy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(e^{xy^2+z^2})

\frac{\partial}{\partial y} (e^{x y^{2} + z^{2}})

e^{x y^{2} + z^{2}} \cdot 2 x y

Solution steps

\frac{\partial}{\partial y} (e^{x y^{2} + z^{2}})

Treat

x, z

as constants

Apply the chain rule:

e^{x y^{2} + z^{2}} \frac{\partial}{\partial y} (x y^{2} + z^{2})

= e^{x y^{2} + z^{2}} \frac{\partial}{\partial y} (x y^{2} + z^{2})

\frac{\partial}{\partial y} (x y^{2} + z^{2}) = 2 x y

= e^{x y^{2} + z^{2}} \cdot 2 x y

x \to 0 lim (- x + 1)

x^{^{'}} = x^{2}, x (0) = - 1

\frac{d}{d x} (\frac{x ^{2}}{100})

\int 5 x^{8} d x

\frac{d}{d x} (\frac{2}{3} x^{9})

What is (\partial)/(\partial y)(e^{xy^2+z^2}) ?
The answer to (\partial)/(\partial y)(e^{xy^2+z^2}) is e^{xy^2+z^2}*2xy