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Popular Calculus >

x^'=x^2,x(0)=-1

Solution

x^{^{'}} = x^{2}, x (0) = - 1

Solution

x = - \frac{1}{t + 1}

Solution steps

x^{'} (t) = x^{2}

Solve separable ODE:

x = - \frac{1}{t + 1}

x = - \frac{1}{t + 1}

Graph

Popular Examples

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\int 5 x^{8} d x

derivative of 2/3 x^9

\frac{d}{d x} (\frac{2}{3} x^{9})

sum from n=-infinity to infinity of 1/n

n = - \infty \sum \infty \frac{1}{n}

derivative of e^{-x}x^2-4e^{-x}x+2e^{-x}

\frac{d}{d x} (e^{- x} x^{2} - 4 e^{- x} x + 2 e^{- x})

tangent of f(x)=x^2-5 tangent of

f (x) = x^{2} - 5

Frequently Asked Questions (FAQ)

What is the solution for x^'=x^2,x(0)=-1 ?
The solution for x^'=x^2,x(0)=-1 is x=-1/(t+1)