What is the tangent of-3x^2+6x+4 ?

The tangent of-3x^2+6x+4 is y=(-6a_{0}+6)x+3a_{0}^2+4

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tangent of-3x^2+6x+4

tangent of

- 3 x^{2} + 6 x + 4

y = (- 6 a_{0} + 6) x + 3 a_{0}^{2} + 4

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 3 a_{0}^{2} + 6 a_{0} + 4)

Find the slope of

y = - 3 x^{2} + 6 x + 4 : \frac{d y}{d x} = - 6 x + 6

Compute the slope of

y = - 3 x^{2} + 6 x + 4

x = a_{0} : m = - 6 a_{0} + 6

Find the line with slope m=

- 6 a_{0} + 6

and passing through

(a_{0}, - 3 a_{0}^{2} + 6 a_{0} + 4) : y = (- 6 a_{0} + 6) x + 3 a_{0}^{2} + 4

y = (- 6 a_{0} + 6) x + 3 a_{0}^{2} + 4

n = 1 \sum \infty n^{5} (1 + n^{6})^{1}

\frac{d y}{d x} = 5 - y

\int e^{3 x} cos (2 x) d x

What is the tangent of-3x^2+6x+4 ?
The tangent of-3x^2+6x+4 is y=(-6a_{0}+6)x+3a_{0}^2+4