What is the sum from n=1 to infinity of n^5(1+n^6)^1 ?

The sum from n=1 to infinity of n^5(1+n^6)^1 is diverges

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sum from n=1 to infinity of n^5(1+n^6)^1

n = 1 \sum \infty n^{5} (1 + n^{6})^{1}

diverges

Solution steps

n = 1 \sum \infty n^{5} (1 + n^{6})^{1}

Apply Series Divergence Test:

diverges

= diverges

\frac{d y}{d x} = 5 - y

\int e^{3 x} cos (2 x) d x

5 x^{2} cos (x) + 4 x

y^{^{''}} - 2 y^{^{'}} - 8 y = 0, y^{^{'}} (0) = 4, y (0) = - 2

What is the sum from n=1 to infinity of n^5(1+n^6)^1 ?
The sum from n=1 to infinity of n^5(1+n^6)^1 is diverges