What is the integral of (sqrt(x))/1 ?

The integral of (sqrt(x))/1 is 2/3 x^{3/2}+C

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integral of (sqrt(x))/1

\int \frac{x}{1} d x

\frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int \frac{x}{1} d x

Simplify

= \int x d x

Apply the Power Rule

: \frac{2}{3} x^{\frac{3}{2}}

= \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} + C

x = 5 y^{2}, x = 1 + 4 y^{2}

3 x^{- \frac{3}{2}} + 6 x^{- \frac{1}{2}} + x^{3} - 4

y = e^{3 x}

\frac{d}{d x} ((x^{2} + 1) e^{x})

2 3 x

What is the integral of (sqrt(x))/1 ?
The integral of (sqrt(x))/1 is 2/3 x^{3/2}+C