What is the integral of sin^{2020}(x ?

The integral of sin^{2020}(x is (x^2sin^{2020}(d))/2+C

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integral of sin^{2020}(x

\int sin^{2020} (d) x d x

\frac{x ^{2} sin ^{2020} ( d )}{2} + C

Solution steps

\int sin^{2020} (d) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin^{2020} (d) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= sin^{2020} (d) \frac{x ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x ^{2} sin ^{2020} ( d )}{2}

Add a constant to the solution

= \frac{x ^{2} sin ^{2020} ( d )}{2} + C

\frac{d}{d x} (- sin (3 x) 3)

\int (2 x + 1)^{- 1} d x

x \to + 0 lim (\frac{2 sin ( 2 x )}{x})

\int \frac{x ^{2}}{x ^{3} + 4} d x

What is the integral of sin^{2020}(x ?
The integral of sin^{2020}(x is (x^2sin^{2020}(d))/2+C