What is the derivative of (x^2-1)/(x^2+4) ?

The derivative of (x^2-1)/(x^2+4) is (10x)/((x^2+4)^2)

What is the first derivative of (x^2-1)/(x^2+4) ?

The first derivative of (x^2-1)/(x^2+4) is (10x)/((x^2+4)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{x ^{2} - 1}{x ^{2} + 4}

\frac{10 x}{( x ^{2} + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 1 ) ( x ^{2} + 4 ) - \frac{d}{d x} ( x ^{2} + 4 ) ( x ^{2} - 1 )}{( x ^{2} + 4 ) ^{2}}

\frac{d}{d x} (x^{2} - 1) = 2 x

\frac{d}{d x} (x^{2} + 4) = 2 x

= \frac{2 x ( x ^{2} + 4 ) - 2 x ( x ^{2} - 1 )}{( x ^{2} + 4 ) ^{2}}

Expand

2 x (x^{2} + 4) - 2 x (x^{2} - 1) : 10 x

= \frac{10 x}{( x ^{2} + 4 ) ^{2}}

\int \frac{ln ( x + 4 )}{x + 4} d x

\int (sec (y) tan (y) - csc (y) cot (y)) d y

y = 1 + 5 x, 1 \leq x \leq 7

7 x e^{x} cos (x)

\int ln (x) + x d x

What is the derivative of (x^2-1)/(x^2+4) ?
The derivative of (x^2-1)/(x^2+4) is (10x)/((x^2+4)^2)
What is the first derivative of (x^2-1)/(x^2+4) ?
The first derivative of (x^2-1)/(x^2+4) is (10x)/((x^2+4)^2)