What is the d/(dt)(cos^2(t)) ?

The d/(dt)(cos^2(t)) is -sin(2t)

What is the first d/(dt)(cos^2(t)) ?

The first d/(dt)(cos^2(t)) is -sin(2t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (cos^{2} (t))

- sin (2 t)

Solution steps

\frac{d}{d t} (cos^{2} (t))

Apply the chain rule:

2 cos (t) \frac{d}{d t} (cos (t))

= 2 cos (t) \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 2 cos (t) (- sin (t))

Simplify

2 cos (t) (- sin (t)) : - sin (2 t)

= - sin (2 t)

\frac{d y}{d x} = \frac{x + 1}{( x ^{2} + 2 x - 3 ) ^{2}}

\frac{d}{d t} (9 cos (t) - cos (9 t))

\int e^{\frac{4 x}{3}} (\frac{4}{3}) d x

- \frac{3 y}{3 x + 2 y}

\int 41 tan^{5} (x) sec^{4} (x) d x