What is the d/(dt)(9cos(t)-cos(9t)) ?

The d/(dt)(9cos(t)-cos(9t)) is -9sin(t)+9sin(9t)

What is the first d/(dt)(9cos(t)-cos(9t)) ?

The first d/(dt)(9cos(t)-cos(9t)) is -9sin(t)+9sin(9t)

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\frac{d}{d t} (9 cos (t) - cos (9 t))

- 9 sin (t) + 9 sin (9 t)

Solution steps

\frac{d}{d t} (9 cos (t) - cos (9 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (9 cos (t)) - \frac{d}{d t} (cos (9 t))

\frac{d}{d t} (9 cos (t)) = - 9 sin (t)

\frac{d}{d t} (cos (9 t)) = - sin (9 t) \cdot 9

= - 9 sin (t) - (- sin (9 t) \cdot 9)

Simplify

= - 9 sin (t) + 9 sin (9 t)

\int e^{\frac{4 x}{3}} (\frac{4}{3}) d x

- \frac{3 y}{3 x + 2 y}

\int 41 tan^{5} (x) sec^{4} (x) d x

x \to 6 lim (\frac{x - 6}{x ^{2} - x})

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + 2 y = 0

What is the d/(dt)(9cos(t)-cos(9t)) ?
The d/(dt)(9cos(t)-cos(9t)) is -9sin(t)+9sin(9t)
What is the first d/(dt)(9cos(t)-cos(9t)) ?
The first d/(dt)(9cos(t)-cos(9t)) is -9sin(t)+9sin(9t)