What is the derivative of f(x)=x^2-8x-91 ?

The derivative of f(x)=x^2-8x-91 is 2x-8

What is the first derivative of f(x)=x^2-8x-91 ?

The first derivative of f(x)=x^2-8x-91 is 2x-8

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derivative of

f (x) = x^{2} - 8 x - 91

2 x - 8

Solution steps

\frac{d}{d x} (x^{2} - 8 x - 91)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 x) - \frac{d}{d x} (91)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (91) = 0

= 2 x - 8 - 0

Simplify

= 2 x - 8

f (x) = \frac{1}{x + 1}, at x = 0

\int 2 cos (x) sin^{2} (x) d x

x + 1

\frac{4 s + 7}{s ^{2} - 4}

\int \frac{x ^{2}}{x ^{2} + 1} d x

What is the derivative of f(x)=x^2-8x-91 ?
The derivative of f(x)=x^2-8x-91 is 2x-8
What is the first derivative of f(x)=x^2-8x-91 ?
The first derivative of f(x)=x^2-8x-91 is 2x-8