What is the (arcsin(3x))^' ?

The (arcsin(3x))^' is 3/(sqrt(1-9x^2))

What is the first (arcsin(3x))^' ?

The first (arcsin(3x))^' is 3/(sqrt(1-9x^2))

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(arcsin (3 x))^{^{'}}

\frac{3}{1 - 9 x ^{2}}

Solution steps

(arcsin (3 x))^{'}

Apply the chain rule:

\frac{1}{1 - ( 3 x ) ^{2}} (3 x)^{'}

= \frac{1}{1 - ( 3 x ) ^{2}} (3 x)^{'}

(3 x)^{'} = 3

= \frac{1}{1 - ( 3 x ) ^{2}} \cdot 3

Simplify

\frac{1}{1 - ( 3 x ) ^{2}} \cdot 3 : \frac{3}{1 - 9 x ^{2}}

= \frac{3}{1 - 9 x ^{2}}

6 x e^{x} csc (x)

\int \frac{2}{x} d x

\int_{- 2}^{2} x^{2} (x^{2} + 1) d x

x = 0, y = (3 x + 1)^{\frac{1}{4}}, [0, 8]

x \to 2 - lim (x^{2})