What is the integral of 2/(sqrt(x)) ?

The integral of 2/(sqrt(x)) is 4sqrt(x)+C

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integral of 2/(sqrt(x))

\int \frac{2}{x} d x

4 x + C

Solution steps

\int \frac{2}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 2 \cdot 2 x^{\frac{1}{2}}

Simplify

2 \cdot 2 x^{\frac{1}{2}} : 4 x

= 4 x

Add a constant to the solution

= 4 x + C

\int_{- 2}^{2} x^{2} (x^{2} + 1) d x

x = 0, y = (3 x + 1)^{\frac{1}{4}}, [0, 8]

x \to 2 - lim (x^{2})

2 x^{2} - 7 x + 5

(x + \frac{4}{x})^{^{'}}