What is the d/(d{x)}(1/(sqrt(9-{x)^2-{y)^2-{z}^2}}) ?

The d/(d{x)}(1/(sqrt(9-{x)^2-{y)^2-{z}^2}}) is ({x})/((9-{x)^2-{y}^2-{z}^2)^{3/2}}

What is the first d/(d{x)}(1/(sqrt(9-{x)^2-{y)^2-{z}^2}}) ?

The first d/(d{x)}(1/(sqrt(9-{x)^2-{y)^2-{z}^2}}) is ({x})/((9-{x)^2-{y}^2-{z}^2)^{3/2}}

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\frac{d}{d x} (\frac{1}{9 - x ^{2} - y ^{2} - z ^{2}})

\frac{x}{( 9 - x ^{2} - y ^{2} - z ^{2} ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{9 - x ^{2} - y ^{2} - z ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((9 - x^{2} - y^{2} - z^{2})^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( 9 - x ^{2} - y ^{2} - z ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (9 - x^{2} - y^{2} - z^{2})

= - \frac{1}{2 ( 9 - x ^{2} - y ^{2} - z ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (9 - x^{2} - y^{2} - z^{2})

\frac{d}{d x} (9 - x^{2} - y^{2} - z^{2}) = - 2 x

= - \frac{1}{2 ( 9 - x ^{2} - y ^{2} - z ^{2} ) ^{\frac{3}{2}}} (- 2 x)

Simplify

- \frac{1}{2 ( 9 - x ^{2} - y ^{2} - z ^{2} ) ^{\frac{3}{2}}} (- 2 x) : \frac{x}{( 9 - x ^{2} - y ^{2} - z ^{2} ) ^{\frac{3}{2}}}

= \frac{x}{( 9 - x ^{2} - y ^{2} - z ^{2} ) ^{\frac{3}{2}}}

- 2 x e^{- x^{2}}

\frac{\partial}{\partial x} (x^{2} y + x + y)

((x - 1)^{2})^{^{'}}

\frac{\partial}{\partial z} (7 z e^{x yz})

\frac{1}{( x ^{2} - 3 ) ( x ^{2} + 3 x + 5 )}

What is the d/(d{x)}(1/(sqrt(9-{x)^2-{y)^2-{z}^2}}) ?
The d/(d{x)}(1/(sqrt(9-{x)^2-{y)^2-{z}^2}}) is ({x})/((9-{x)^2-{y}^2-{z}^2)^{3/2}}
What is the first d/(d{x)}(1/(sqrt(9-{x)^2-{y)^2-{z}^2}}) ?
The first d/(d{x)}(1/(sqrt(9-{x)^2-{y)^2-{z}^2}}) is ({x})/((9-{x)^2-{y}^2-{z}^2)^{3/2}}