What is the tangent of y=x^2-1,(5,24) ?

The tangent of y=x^2-1,(5,24) is y=10x-26

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tangent of y=x^2-1,(5,24)

tangent of

y = x^{2} - 1, (5, 24)

y = 10 x - 26

Solution steps

Find the slope of

y = x^{2} - 1 : \frac{d y}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 10

Find the line with slope m=

10

and passing through

(5, 24) : y = 10 x - 26

y = 10 x - 26

\frac{d}{d x} (x^{5} \cdot ln (x))

\frac{d}{d x} (x^{2} - a^{2})

n = 0 \sum \infty \frac{1}{3 ^{n - 1}}

y = \frac{1}{ln ( x )}

x \to 5 lim (\frac{x}{∣ x - 5 ∣})

What is the tangent of y=x^2-1,(5,24) ?
The tangent of y=x^2-1,(5,24) is y=10x-26