What is the sum from n=1 to infinity of nsin(npi) ?

The sum from n=1 to infinity of nsin(npi) is 0

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sum from n=1 to infinity of nsin(npi)

n = 1 \sum \infty n sin (nπ)

0

Solution steps

n = 1 \sum \infty n sin (nπ)

n sin (nπ) = 0

= n = 1 \sum \infty 0

\sum 0 = 0

= 0

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What is the sum from n=1 to infinity of nsin(npi) ?
The sum from n=1 to infinity of nsin(npi) is 0