What is the derivative of (ln(5x)/(5x)) ?

The derivative of (ln(5x)/(5x)) is (1-ln(5x))/(5x^2)

What is the first derivative of (ln(5x)/(5x)) ?

The first derivative of (ln(5x)/(5x)) is (1-ln(5x))/(5x^2)

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\frac{d}{d x} (\frac{ln ( 5 x )}{5 x})

\frac{1 - ln ( 5 x )}{5 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{ln ( 5 x )}{5 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} (\frac{ln ( 5 x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{5} \cdot \frac{\frac{d}{d x} ( ln ( 5 x ) ) x - \frac{d x}{d x} ln ( 5 x )}{x ^{2}}

\frac{d}{d x} (ln (5 x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= \frac{1}{5} \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( 5 x )}{x ^{2}}

Simplify

\frac{1}{5} \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( 5 x )}{x ^{2}} : \frac{1 - ln ( 5 x )}{5 x ^{2}}

= \frac{1 - ln ( 5 x )}{5 x ^{2}}

1. 5^{x}

\int \frac{x}{9 - x ^{2}} d x

\int \frac{1}{sin ^{2} ( 3 x )} d x

\frac{d y}{d x} = \frac{sec ( y )}{( x - 3 ) ^{2}}

\frac{d y}{d x} - 2 x y = x y^{2}

What is the derivative of (ln(5x)/(5x)) ?
The derivative of (ln(5x)/(5x)) is (1-ln(5x))/(5x^2)
What is the first derivative of (ln(5x)/(5x)) ?
The first derivative of (ln(5x)/(5x)) is (1-ln(5x))/(5x^2)