What is the solution for (dy)/(dx)-2xy=xy^2 ?

The solution for (dy)/(dx)-2xy=xy^2 is y= 2/(e^{-x^2-c_{1)}-1}

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(dy)/(dx)-2xy=xy^2

\frac{d y}{d x} - 2 x y = x y^{2}

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

Solution steps

\frac{d y}{d x} - 2 x y = x y^{2}

Solve Bernoulli ODE:

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

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\int_{0}^{1} 8 cos (x^{2}) d x

f (x) = 2 + 2 e^{- x}, at x = ln (5)

\frac{1}{6 x ^{3}}

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What is the solution for (dy)/(dx)-2xy=xy^2 ?
The solution for (dy)/(dx)-2xy=xy^2 is y= 2/(e^{-x^2-c_{1)}-1}