What is the derivative of 1/(6x^3) ?

The derivative of 1/(6x^3) is -1/(2x^4)

What is the first derivative of 1/(6x^3) ?

The first derivative of 1/(6x^3) is -1/(2x^4)

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derivative of

\frac{1}{6 x ^{3}}

- \frac{1}{2 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{1}{6 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{6} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{6} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{6} (- 3 x^{- 3 - 1})

Simplify

\frac{1}{6} (- 3 x^{- 3 - 1}) : - \frac{1}{2 x ^{4}}

= - \frac{1}{2 x ^{4}}

\int sin (x) cos^{4} (x) d x

81 y^{^{''}} + 180 y^{^{'}} + 100 y = 0

\int_{0}^{20} 3 x d x

\int \frac{1}{t ^{2} 100 - t ^{2}} d t

x \to 0 lim (ln (cos (x)))

What is the derivative of 1/(6x^3) ?
The derivative of 1/(6x^3) is -1/(2x^4)
What is the first derivative of 1/(6x^3) ?
The first derivative of 1/(6x^3) is -1/(2x^4)