What is the derivative of x^4-x^2 ?

The derivative of x^4-x^2 is 4x^3-2x

What is the first derivative of x^4-x^2 ?

The first derivative of x^4-x^2 is 4x^3-2x

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\frac{d}{d x} (x^{4} - x^{2})

4 x^{3} - 2 x

Solution steps

\frac{d}{d x} (x^{4} - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (x^{2}) = 2 x

= 4 x^{3} - 2 x

\int tan (5 x) d x

\frac{d}{d x} (\frac{x ^{2} - 2 x + 5}{x ^{2} + 9})

\int (- \frac{3}{10 - 10 x ^{2}}) d x

y = 3 tan (2 x)

\int \frac{- 6}{x ^{2} x ^{2} - 9} d x

What is the derivative of x^4-x^2 ?
The derivative of x^4-x^2 is 4x^3-2x
What is the first derivative of x^4-x^2 ?
The first derivative of x^4-x^2 is 4x^3-2x