What is the solution for (dy)/(dt)=y^3-y ?

The solution for (dy)/(dt)=y^3-y is y=sqrt(1/(-e^{2t+c_{1))+1}},y=-sqrt(1/(-e^{2t+c_{1))+1}}

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(dy)/(dt)=y^3-y

\frac{d y}{d t} = y^{3} - y

y = \frac{1}{- e ^{2 t + c_{1}} + 1}, y = - \frac{1}{- e ^{2 t + c_{1}} + 1}

Solution steps

\frac{d y}{d t} = y^{3} - y

Solve Bernoulli ODE:

y = \frac{1}{- e ^{2 t + c_{1}} + 1}, y = - \frac{1}{- e ^{2 t + c_{1}} + 1}

y = \frac{1}{- e ^{2 t + c_{1}} + 1}, y = - \frac{1}{- e ^{2 t + c_{1}} + 1}

\int \frac{1}{x 7 x - 1} d x

\frac{d}{d x} (e^{c o s (2 x)})

cos (π - 4 x)

\int \frac{3}{125} x^{2} d x

x \to 0 lim (4 x)

What is the solution for (dy)/(dt)=y^3-y ?
The solution for (dy)/(dt)=y^3-y is y=sqrt(1/(-e^{2t+c_{1))+1}},y=-sqrt(1/(-e^{2t+c_{1))+1}}