What is the integral of 3/125 x^2 ?

The integral of 3/125 x^2 is (x^3)/(125)+C

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integral of 3/125 x^2

\int \frac{3}{125} x^{2} d x

\frac{x ^{3}}{125} + C

Solution steps

\int \frac{3}{125} x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{125} \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= \frac{3}{125} \cdot \frac{x ^{3}}{3}

Simplify

\frac{3}{125} \cdot \frac{x ^{3}}{3} : \frac{x ^{3}}{125}

= \frac{x ^{3}}{125}

Add a constant to the solution

= \frac{x ^{3}}{125} + C

x \to 0 lim (4 x)

\int (\frac{3}{x ^{2}} - \frac{2}{x ^{3}}) d x

n = 1 \sum \infty \frac{n !}{n \cdot 3 ^{n}}

y = 18 sin (x), y = 18 cos (x)

x^{2} - 4 x + 3, - x^{2} + 2 x + 3, 4, 0