What is the derivative of (x+iy)^2 ?

The derivative of (x+iy)^2 is 2x+2iy

What is the first derivative of (x+iy)^2 ?

The first derivative of (x+iy)^2 is 2x+2iy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

(x + i y)^{2}

2 x + 2 i y

Solution steps

\frac{d}{d x} ((x + i y)^{2})

Treat

y

as a constant

Apply the chain rule:

2 (x + i y) \frac{d}{d x} (x + i y)

= 2 (x + i y) \frac{d}{d x} (x + i y)

\frac{d}{d x} (x + i y) = 1

= 2 (x + i y) \cdot 1

Simplify

2 (x + i y) \cdot 1 : 2 x + 2 i y

= 2 x + 2 i y

y^{^{'}} + (\frac{2}{x}) y = 0

\int (\frac{1 - x}{x})^{2} d x

f (x) = 5 + 5 x^{2} - 2 x^{3}, at x = 2

\frac{\partial}{\partial x} (\frac{G ( m , x ) m}{x ^{2}})

\int \frac{- 3 e ^{5 x}}{5 x} d x

What is the derivative of (x+iy)^2 ?
The derivative of (x+iy)^2 is 2x+2iy
What is the first derivative of (x+iy)^2 ?
The first derivative of (x+iy)^2 is 2x+2iy