What is the tangent of x^2+y^2=169,(12,-5) ?

The tangent of x^2+y^2=169,(12,-5) is y= 12/5 x-169/5

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tangent of x^2+y^2=169,(12,-5)

tangent of

x^{2} + y^{2} = 169, (12, - 5)

y = \frac{12}{5} x - \frac{169}{5}

Solution steps

Find the slope of

x^{2} + y^{2} = 169 : \frac{d y}{d x} = - \frac{x}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{12}{5}

Find the line with slope m=

\frac{12}{5}

and passing through

(12, - 5) : y = \frac{12}{5} x - \frac{169}{5}

y = \frac{12}{5} x - \frac{169}{5}

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\int_{- 2}^{3} (8 z^{3} + 3 z - 1) d z

\int_{1}^{\infty} \frac{( e ^{- x} )}{x} d x

\int 75 - 10 x - x^{2} d x

y^{^{''}} - y^{^{'}} - 2 y = - 4 t + 8 t^{2}

What is the tangent of x^2+y^2=169,(12,-5) ?
The tangent of x^2+y^2=169,(12,-5) is y= 12/5 x-169/5