What is the integral from-2 to 3 of (8z^3+3z-1) ?

The integral from-2 to 3 of (8z^3+3z-1) is 265/2

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integral from-2 to 3 of (8z^3+3z-1)

\int_{- 2}^{3} (8 z^{3} + 3 z - 1) d z

\frac{265}{2}

Decimal

132.5

Solution steps

\int_{- 2}^{3} 8 z^{3} + 3 z - 1 d z

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{3} 8 z^{3} d z + \int_{- 2}^{3} 3 z d z - \int_{- 2}^{3} 1 d z

\int_{- 2}^{3} 8 z^{3} d z = 130

\int_{- 2}^{3} 3 z d z = \frac{15}{2}

\int_{- 2}^{3} 1 d z = 5

= 130 + \frac{15}{2} - 5

Simplify

130 + \frac{15}{2} - 5 : \frac{265}{2}

= \frac{265}{2}

\int_{1}^{\infty} \frac{( e ^{- x} )}{x} d x

\int 75 - 10 x - x^{2} d x

y^{^{''}} - y^{^{'}} - 2 y = - 4 t + 8 t^{2}

y = x - 2, y = x^{2} - 4, x = 5

\int y cos (z) d z

What is the integral from-2 to 3 of (8z^3+3z-1) ?
The integral from-2 to 3 of (8z^3+3z-1) is 265/2