What is the integral of ycos(z) ?

The integral of ycos(z) is ysin(z)+C

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integral of ycos(z)

\int y cos (z) d z

y sin (z) + C

Solution steps

\int y cos (z) d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= y \cdot \int cos (z) d z

Use the common integral:

\int cos (z) d z = sin (z)

= y sin (z)

Add a constant to the solution

= y sin (z) + C

x y = (- 1 - x^{2}) y^{^{'}}

\int 2 x^{- \frac{1}{2}} d x

7 (4 x^{2} - 7 x + 2)^{- 6}

x \to \infty lim (x^{2} + 5)

x \to 2 - lim (\frac{x - 1}{x - 2})